annotate Python/getcopyright.c @ 58973:db86bf39ccaa legacy-trunk

Issue 7970: When email.Parser.Parser parses a MIME message of type message/rfc822 it turns it into an object whose body consists of a list containing a single Message object. HeaderParser, on the other hand, just copies the body as a string. Generator.flatten has a special handler for the message mime type that expected the body to be the one item list. This fails if the message was parsed by HeaderParser. So we now check to see if the body is a string first, and if so just we just emit it.
author R. David Murray <rdmurray@bitdance.com>
date Sun, 21 Feb 2010 04:23:00 +0000
parents 1d0fde59ddea
children 7bb37a4cd7cf 550b38caf5c1
Ignore whitespace changes - Everywhere: Within whitespace: At end of lines:
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1 /* Return the copyright string. This is updated manually. */
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2
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237c3b2a6187 include Python.h
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3 #include "Python.h"
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4
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e2e436a62898 At Bob Kahn's request, add CNRI to the copyright string (but not to
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5 static char cprt[] =
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6 "\
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7 Copyright (c) 2001-2010 Python Software Foundation.\n\
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8 All Rights Reserved.\n\
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9 \n\
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10 Copyright (c) 2000 BeOpen.com.\n\
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11 All Rights Reserved.\n\
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12 \n\
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13 Copyright (c) 1995-2001 Corporation for National Research Initiatives.\n\
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14 All Rights Reserved.\n\
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15 \n\
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16 Copyright (c) 1991-1995 Stichting Mathematisch Centrum, Amsterdam.\n\
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17 All Rights Reserved.";
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18
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19 const char *
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20 Py_GetCopyright(void)
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21 {
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22 return cprt;
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23 }