annotate Doc/includes/sqlite3/execsql_fetchonerow.py @ 58925:eecf1bef052d 2.6

Merged revisions 78207 via svnmerge from svn+ssh://pythondev@svn.python.org/python/trunk ........ r78207 | ezio.melotti | 2010-02-17 01:26:09 +0200 (Wed, 17 Feb 2010) | 1 line #7930: fix stripid ........
author Ezio Melotti <ezio.melotti@gmail.com>
date Tue, 16 Feb 2010 23:29:44 +0000
parents c62f6669ae22
children
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1 import sqlite3
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2
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3 con = sqlite3.connect("mydb")
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5 cur = con.cursor()
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6 SELECT = "select name_last, age from people order by age, name_last"
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7
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8 # 1. Iterate over the rows available from the cursor, unpacking the
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9 # resulting sequences to yield their elements (name_last, age):
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10 cur.execute(SELECT)
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11 for (name_last, age) in cur:
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12 print '%s is %d years old.' % (name_last, age)
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13
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14 # 2. Equivalently:
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15 cur.execute(SELECT)
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16 for row in cur:
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17 print '%s is %d years old.' % (row[0], row[1])