view Python/fmod.c @ 16845:09dcf5ebcd80 legacy-trunk

Now that Jeremy is asking about this code, it looks really bogus to me, so let's rip it out. The constructor for SyntaxError does the right thing, so we do not need to do it again.
author Fred Drake <fdrake@acm.org>
date Wed, 28 Feb 2001 20:58:04 +0000
parents 6f6f965c5e2d
children 2dea40e40d9d
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/* Portable fmod(x, y) implementation for systems that don't have it */

#include "config.h"

#include "pyport.h"
#include <errno.h>

double
fmod(double x, double y)
{
	double i, f;
	
	if (y == 0.0) {
		errno = EDOM;
		return 0.0;
	}
	
	/* return f such that x = i*y + f for some integer i
	   such that |f| < |y| and f has the same sign as x */
	
	i = floor(x/y);
	f = x - i*y;
	if ((x < 0.0) != (y < 0.0))
		f = f-y;
	return f;
}