view Python/getcopyright.c @ 16845:09dcf5ebcd80 legacy-trunk

Now that Jeremy is asking about this code, it looks really bogus to me, so let's rip it out. The constructor for SyntaxError does the right thing, so we do not need to do it again.
author Fred Drake <fdrake@acm.org>
date Wed, 28 Feb 2001 20:58:04 +0000
parents 17f23f8cd8c7
children 9237f58dcc19
line wrap: on
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/* Return the copyright string.  This is updated manually. */

#include "Python.h"

static char cprt[] = 
"\
Copyright (c) 2000, 2001 Guido van Rossum.\n\
All Rights Reserved.\n\
\n\
Copyright (c) 2000 BeOpen.com.\n\
All Rights Reserved.\n\
\n\
Copyright (c) 1995-2000 Corporation for National Research Initiatives.\n\
All Rights Reserved.\n\
\n\
Copyright (c) 1991-1995 Stichting Mathematisch Centrum, Amsterdam.\n\
All Rights Reserved.";

const char *
Py_GetCopyright(void)
{
	return cprt;
}